Integrand size = 29, antiderivative size = 148 \[ \int \cot ^2(c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {a b \text {arctanh}(\cos (c+d x))}{4 d}+\frac {\left (2 a^2+5 b^2\right ) \cot (c+d x)}{15 d}+\frac {a b \cot (c+d x) \csc (c+d x)}{4 d}+\frac {\left (a^2-2 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{15 d}-\frac {a b \cot (c+d x) \csc ^3(c+d x)}{10 d}-\frac {\cot (c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2}{5 d} \]
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Time = 0.26 (sec) , antiderivative size = 148, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.310, Rules used = {2968, 3127, 3110, 3100, 2827, 3853, 3855, 3852, 8} \[ \int \cot ^2(c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {\left (2 a^2+5 b^2\right ) \cot (c+d x)}{15 d}+\frac {\left (a^2-2 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{15 d}+\frac {a b \text {arctanh}(\cos (c+d x))}{4 d}-\frac {a b \cot (c+d x) \csc ^3(c+d x)}{10 d}+\frac {a b \cot (c+d x) \csc (c+d x)}{4 d}-\frac {\cot (c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2}{5 d} \]
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Rule 8
Rule 2827
Rule 2968
Rule 3100
Rule 3110
Rule 3127
Rule 3852
Rule 3853
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \int \csc ^6(c+d x) (a+b \sin (c+d x))^2 \left (1-\sin ^2(c+d x)\right ) \, dx \\ & = -\frac {\cot (c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2}{5 d}+\frac {1}{5} \int \csc ^5(c+d x) (a+b \sin (c+d x)) \left (2 b-a \sin (c+d x)-3 b \sin ^2(c+d x)\right ) \, dx \\ & = -\frac {a b \cot (c+d x) \csc ^3(c+d x)}{10 d}-\frac {\cot (c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2}{5 d}-\frac {1}{20} \int \csc ^4(c+d x) \left (4 \left (a^2-2 b^2\right )+10 a b \sin (c+d x)+12 b^2 \sin ^2(c+d x)\right ) \, dx \\ & = \frac {\left (a^2-2 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{15 d}-\frac {a b \cot (c+d x) \csc ^3(c+d x)}{10 d}-\frac {\cot (c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2}{5 d}-\frac {1}{60} \int \csc ^3(c+d x) \left (30 a b+4 \left (2 a^2+5 b^2\right ) \sin (c+d x)\right ) \, dx \\ & = \frac {\left (a^2-2 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{15 d}-\frac {a b \cot (c+d x) \csc ^3(c+d x)}{10 d}-\frac {\cot (c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2}{5 d}-\frac {1}{2} (a b) \int \csc ^3(c+d x) \, dx-\frac {1}{15} \left (2 a^2+5 b^2\right ) \int \csc ^2(c+d x) \, dx \\ & = \frac {a b \cot (c+d x) \csc (c+d x)}{4 d}+\frac {\left (a^2-2 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{15 d}-\frac {a b \cot (c+d x) \csc ^3(c+d x)}{10 d}-\frac {\cot (c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2}{5 d}-\frac {1}{4} (a b) \int \csc (c+d x) \, dx+\frac {\left (2 a^2+5 b^2\right ) \text {Subst}(\int 1 \, dx,x,\cot (c+d x))}{15 d} \\ & = \frac {a b \text {arctanh}(\cos (c+d x))}{4 d}+\frac {\left (2 a^2+5 b^2\right ) \cot (c+d x)}{15 d}+\frac {a b \cot (c+d x) \csc (c+d x)}{4 d}+\frac {\left (a^2-2 b^2\right ) \cot (c+d x) \csc ^2(c+d x)}{15 d}-\frac {a b \cot (c+d x) \csc ^3(c+d x)}{10 d}-\frac {\cot (c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2}{5 d} \\ \end{align*}
Time = 1.29 (sec) , antiderivative size = 236, normalized size of antiderivative = 1.59 \[ \int \cot ^2(c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {\csc ^5(c+d x) \left (-40 \left (4 a^2+b^2\right ) \cos (c+d x)+20 \left (-2 a^2+b^2\right ) \cos (3 (c+d x))+8 a^2 \cos (5 (c+d x))+20 b^2 \cos (5 (c+d x))+150 a b \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right ) \sin (c+d x)-150 a b \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right ) \sin (c+d x)-180 a b \sin (2 (c+d x))-75 a b \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right ) \sin (3 (c+d x))+75 a b \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right ) \sin (3 (c+d x))-30 a b \sin (4 (c+d x))+15 a b \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right ) \sin (5 (c+d x))-15 a b \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right ) \sin (5 (c+d x))\right )}{960 d} \]
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Time = 0.44 (sec) , antiderivative size = 135, normalized size of antiderivative = 0.91
method | result | size |
derivativedivides | \(\frac {a^{2} \left (-\frac {\cos ^{3}\left (d x +c \right )}{5 \sin \left (d x +c \right )^{5}}-\frac {2 \left (\cos ^{3}\left (d x +c \right )\right )}{15 \sin \left (d x +c \right )^{3}}\right )+2 a b \left (-\frac {\cos ^{3}\left (d x +c \right )}{4 \sin \left (d x +c \right )^{4}}-\frac {\cos ^{3}\left (d x +c \right )}{8 \sin \left (d x +c \right )^{2}}-\frac {\cos \left (d x +c \right )}{8}-\frac {\ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{8}\right )-\frac {b^{2} \left (\cos ^{3}\left (d x +c \right )\right )}{3 \sin \left (d x +c \right )^{3}}}{d}\) | \(135\) |
default | \(\frac {a^{2} \left (-\frac {\cos ^{3}\left (d x +c \right )}{5 \sin \left (d x +c \right )^{5}}-\frac {2 \left (\cos ^{3}\left (d x +c \right )\right )}{15 \sin \left (d x +c \right )^{3}}\right )+2 a b \left (-\frac {\cos ^{3}\left (d x +c \right )}{4 \sin \left (d x +c \right )^{4}}-\frac {\cos ^{3}\left (d x +c \right )}{8 \sin \left (d x +c \right )^{2}}-\frac {\cos \left (d x +c \right )}{8}-\frac {\ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{8}\right )-\frac {b^{2} \left (\cos ^{3}\left (d x +c \right )\right )}{3 \sin \left (d x +c \right )^{3}}}{d}\) | \(135\) |
parallelrisch | \(\frac {-3 a^{2} \left (\cot ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+3 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2}-15 a b \left (\cot ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+15 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b -5 a^{2} \left (\cot ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-20 b^{2} \left (\cot ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+5 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{2}+20 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}+30 a^{2} \cot \left (\frac {d x}{2}+\frac {c}{2}\right )+60 b^{2} \cot \left (\frac {d x}{2}+\frac {c}{2}\right )-30 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) a^{2}-60 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{2}-120 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b}{480 d}\) | \(203\) |
risch | \(-\frac {-60 i b^{2} {\mathrm e}^{8 i \left (d x +c \right )}+15 a b \,{\mathrm e}^{9 i \left (d x +c \right )}+120 i a^{2} {\mathrm e}^{6 i \left (d x +c \right )}+120 i b^{2} {\mathrm e}^{6 i \left (d x +c \right )}+90 a b \,{\mathrm e}^{7 i \left (d x +c \right )}+40 i a^{2} {\mathrm e}^{4 i \left (d x +c \right )}-80 i b^{2} {\mathrm e}^{4 i \left (d x +c \right )}+40 i a^{2} {\mathrm e}^{2 i \left (d x +c \right )}+40 i b^{2} {\mathrm e}^{2 i \left (d x +c \right )}-90 a b \,{\mathrm e}^{3 i \left (d x +c \right )}-8 i a^{2}-20 i b^{2}-15 a b \,{\mathrm e}^{i \left (d x +c \right )}}{30 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{5}}-\frac {a b \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{4 d}+\frac {a b \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{4 d}\) | \(228\) |
norman | \(\frac {-\frac {a^{2}}{160 d}+\frac {a^{2} \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{160 d}+\frac {\left (5 a^{2}+8 b^{2}\right ) \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{96 d}-\frac {\left (5 a^{2}+8 b^{2}\right ) \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{96 d}-\frac {\left (11 a^{2}+20 b^{2}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{480 d}+\frac {\left (11 a^{2}+20 b^{2}\right ) \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{480 d}+\frac {\left (17 a^{2}+20 b^{2}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{480 d}-\frac {\left (17 a^{2}+20 b^{2}\right ) \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{480 d}-\frac {a b \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}-\frac {a b \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}-\frac {a b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{32 d}-\frac {a b \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}+\frac {a b \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}+\frac {a b \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32 d}}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}-\frac {a b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4 d}\) | \(342\) |
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Time = 0.28 (sec) , antiderivative size = 195, normalized size of antiderivative = 1.32 \[ \int \cot ^2(c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {8 \, {\left (2 \, a^{2} + 5 \, b^{2}\right )} \cos \left (d x + c\right )^{5} - 40 \, {\left (a^{2} + b^{2}\right )} \cos \left (d x + c\right )^{3} + 15 \, {\left (a b \cos \left (d x + c\right )^{4} - 2 \, a b \cos \left (d x + c\right )^{2} + a b\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) \sin \left (d x + c\right ) - 15 \, {\left (a b \cos \left (d x + c\right )^{4} - 2 \, a b \cos \left (d x + c\right )^{2} + a b\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) \sin \left (d x + c\right ) - 30 \, {\left (a b \cos \left (d x + c\right )^{3} + a b \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{120 \, {\left (d \cos \left (d x + c\right )^{4} - 2 \, d \cos \left (d x + c\right )^{2} + d\right )} \sin \left (d x + c\right )} \]
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Timed out. \[ \int \cot ^2(c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2 \, dx=\text {Timed out} \]
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Time = 0.21 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.73 \[ \int \cot ^2(c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2 \, dx=-\frac {15 \, a b {\left (\frac {2 \, {\left (\cos \left (d x + c\right )^{3} + \cos \left (d x + c\right )\right )}}{\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{2} + 1} - \log \left (\cos \left (d x + c\right ) + 1\right ) + \log \left (\cos \left (d x + c\right ) - 1\right )\right )} + \frac {40 \, b^{2}}{\tan \left (d x + c\right )^{3}} + \frac {8 \, {\left (5 \, \tan \left (d x + c\right )^{2} + 3\right )} a^{2}}{\tan \left (d x + c\right )^{5}}}{120 \, d} \]
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Time = 0.36 (sec) , antiderivative size = 222, normalized size of antiderivative = 1.50 \[ \int \cot ^2(c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {3 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 15 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 5 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 20 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 120 \, a b \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right ) - 30 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 60 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + \frac {274 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 30 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 60 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 5 \, a^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 20 \, b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 15 \, a b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 3 \, a^{2}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5}}}{480 \, d} \]
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Time = 10.78 (sec) , antiderivative size = 187, normalized size of antiderivative = 1.26 \[ \int \cot ^2(c+d x) \csc ^4(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{160\,d}-\frac {{\mathrm {cot}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (\frac {a^2}{3}+\frac {4\,b^2}{3}\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (2\,a^2+4\,b^2\right )+\frac {a^2}{5}+a\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{32\,d}-\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (\frac {a^2}{16}+\frac {b^2}{8}\right )}{d}+\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (\frac {a^2}{96}+\frac {b^2}{24}\right )}{d}+\frac {a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{32\,d}-\frac {a\,b\,\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{4\,d} \]
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